MCQ
Among $NH_3 , PH_3 , AsH_3$ and $SbH_3$ which one is a stronger reducing agent?
- A$NH_3$
- B$PH_3$
- C$AsH_3$
- ✓$SbH_3$
✓
Answer
Correct option: D.
$SbH_3$
d
$SbH _3$ is the strongest reducing agent because $Sb ^{5+}$ is most stable in its respective group so it gets easily oxidised so its the strongest reducing agent.
$SbH _3$ is the strongest reducing agent because $Sb ^{5+}$ is most stable in its respective group so it gets easily oxidised so its the strongest reducing agent.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The products A and B in the following reactions, respectively are
$\mathrm{A} \stackrel{\mathrm{Ag}_{\mathrm{N}}-\mathrm{NO}_{2}}{ } \mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{Br} \xrightarrow{\mathrm{AgCN}} \mathrm{B}$
→According to molecular orbital theory, the number of unpaired electron(s) in $\mathrm{O}_{2}^{2-}$ is :
→Among given species identify the isostructural pairs
Arrange the following in decreasing order of $BP$
→$CH_3CHO$ $( I )$, $CH_3CH_2OH$ $( II )$
$CH_3OCH_3$ $( III )$, $CH_3CH_2CH_3$ $( IV )$
The wave number of the first emission line in the Balmer series of $H-$ Spectrum is ( $R =$ Rydberg constant)
→Which of the following structures represents the lowest-energy form of $(1S, 2S,
4R)$ -trimethyl -cyclohexane?
→4R)$ -trimethyl -cyclohexane?
Which of the following orders of rotation barrier about the $C = C$ bond, as indicated, is correct ?
→Identify the mixture that shows positive deviations from Raoult's Law
Chloroform when treated with aniline and alcoholic $KOH$ gives
→A tertiary butyl carbocation is more stable than a secondary butyl carbocation because of which of the following$?$
→