MCQ
Among the following ions the $p\pi - d\pi $ overlap could be present in
- A$NO_2^ - $
- B$NO_3^ - $
- ✓$PO_4^{ - 3}$
- D$CO_3^{ - 2}$
✓
Answer
Correct option: C.
$PO_4^{ - 3}$
c
In $P=O$ bond, $\pi$ - bond is formed by the sidewise overlapping of $d$ - orbital of $P$ and $p$ - orbital of oxygen. Hence, it is formed by $p \pi$ and $d\pi$ overlapping.
In $P=O$ bond, $\pi$ - bond is formed by the sidewise overlapping of $d$ - orbital of $P$ and $p$ - orbital of oxygen. Hence, it is formed by $p \pi$ and $d\pi$ overlapping.
In nitrogen and carbon, no vacant $d$-orbital is present. So, they do not form $p \pi- d \pi$ bond.
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