MCQ
Among the following the compound that is both paramagnetic and coloured is
- A$K_2Cr_2O_7$
- B$(NH_4)_2 [TiCl_6]$
- ✓$VOSO_4$
- D$K_3Cu (CN)_4$
$(b)$ In ${(N{H_4})_2}[TiC{l_6}]\,Ti$ is in $+4$ oxidation state, hence has no unpaired electron hence colourless and diamagnetic.
$(c)$ In $VOSO_4$, is in $+4$ oxidation state, hence has no unpaired electron ,thus it is coloured and paramagnetic.
$(a)$ In $K_2Cr_2O_7$ $Cr$ is in $+6$ oxidation state, hence has no unpaired electron and thus it is diamagnetic. Though $K_2Cr_2O_7$ has no unpaired electron but it is coloured. this is due to charge transfer.
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Use : $\frac{{2.303RT}}{F}$ = $0.06$
Time Rate (mole $litre^{-1}\,sec^{ -1}$ )
$0$ $2.8 \times {10^{ - 2}}$
$10$ $2.78 \times {10^{ - 2}}$
$20 $ $2.81 \times {10^{ - 2}}$
$30$ $2.79 \times {10^{ - 2}}$
The reaction is