MCQ
Among the following the compound that is both paramagnetic and coloured is
- A$K_2Cr_2O_7$
- B$(NH_4)_2 [TiCl_6]$
- ✓$VOSO_4$
- D$K_3Cu (CN)_4$
✓
Answer
Correct option: C.
$VOSO_4$
c
$(d)$ In $K_3[Cu(CN)_4]$ $Cu$ is in $+1$ oxidation state hence has no unpaired electron hence colourless and diamagnetic.
$(d)$ In $K_3[Cu(CN)_4]$ $Cu$ is in $+1$ oxidation state hence has no unpaired electron hence colourless and diamagnetic.
$(b)$ In ${(N{H_4})_2}[TiC{l_6}]\,Ti$ is in $+4$ oxidation state, hence has no unpaired electron hence colourless and diamagnetic.
$(c)$ In $VOSO_4$, is in $+4$ oxidation state, hence has no unpaired electron ,thus it is coloured and paramagnetic.
$(a)$ In $K_2Cr_2O_7$ $Cr$ is in $+6$ oxidation state, hence has no unpaired electron and thus it is diamagnetic. Though $K_2Cr_2O_7$ has no unpaired electron but it is coloured. this is due to charge transfer.
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