


$(A)$ $X = COOCH _3, Y = H _2 /$ Ni/heat
$(B)$ $X = CONH _2, Y = H _2 /$ Ni/heat
$(C)$ $X = CONH _2, Y = Br _2 / NaOH$
$(D)$ $X = CN , Y = H _2 /$ Ni/heat

In the above reaction, $3.9\, g$ of benzene on nitration gives $4.92\, g$ of nitrobenzene. The percentage yield of nitrobenzene in the above reaction is............. $\%$. (Round off to the Nearest Integer).
(Given atomic mass: $C : 12.0\, u , H : 1.0\, u$$O : 16.0\, u , N : 14.0\, u )$