- A$C_6H_5CH_2NH_2$
- B$C_6H_5CH_2NHCH_3$
- C$NO_2CH_2NH_2$
- ✓$CH_3NHCHO$
$C_{6} H_{5} N H C H_{3}>C_{6} H_{5} C H_{2} N H_{2}>O_{2} N C H_{2} N H_{2}>C H_{3} N H C H O$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$(A)$ ${SO}_{3}$ $(B)$ ${NO}_{3}^{-}$ $(C)$ ${PCl}_{3}$ $(D)$ ${CO}_{3}^{2-}$
$(A)$ The decreasing order of atomic radii of group $13$ elements is $\mathrm{Tl}>\mathrm{In}>\mathrm{Ga}>\mathrm{Al}>\mathrm{B}$.
$(B)$ Down the group $13$ electronegativity decreases from top to bottom.
$(C)$ $\mathrm{Al}$ dissolves in dil. $\mathrm{HCl}$ and liberate $\mathrm{H}_2$ but conc. $\mathrm{HNO}_3$ renders Al passive by forming a protective oxide layer on the surface.
$(D)$ All elements of group 13 exhibits highly stable +1 oxidation state.
$(E)$ Hybridisation of $\mathrm{Al}$ in $\left[\mathrm{Al}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+}$ ion is $\mathrm{sp}^3 \mathrm{~d}^2$.
Choose the correct answer from the options given below: