Question
Amongst the following elements, the highest ionization energy is
Thus among given option highest IE is of option B i.e. $[N e] 3 s^{2} 3 p^{3}$.
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$(i)$ ${C_4}{H_5}N{H_2}$ $(ii)$ $C{H_3}N{H_2}$
$(iii)$ ${(C{H_3})_2}NH$ $ (iv)$ ${(C{H_3})_3}N$
[Given $\sqrt2 = 1.41$]
${{O}_{(g)}}+{{e}^{-}}=O_{(g)}^{-}\Delta {{H}^{o}}=-142\ kJ\,mo{{l}^{-1}}$
$O_{(g)}^{-}+{{e}^{-}}=O_{(g)}^{2-}\Delta {{H}^{o}}=844\ kJ\,mo{{l}^{-1}}$
${C_{\left( s \right)}} + {H_2}{O_{\left( g \right)}} \rightleftharpoons C{O_{\left( g \right)}} + {H_{2\left( g \right)}}$