MCQ
An ac source is connected to a capacitor $C$. Due to decrease in its operating frequency :
- Acapacitive reactance remains constant.
- Bcapacitive reactance decreases.
- Cdisplacement current increases.
- ✓displacement current decreases.
✓
Answer
Correct option: D.
displacement current decreases.
d
$i _{ C }= i _{ D }=\frac{ V _{ O }}{ X _{ C }} \sin \omega t$
$i _{ C }= i _{ D }=\frac{ V _{ O }}{ X _{ C }} \sin \omega t$
$i _{ C }= i _{ D }=\left( V _{ O } \omega C \right) \sin \omega t$
On decreasing frequency $i_C \downarrow$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The equivalent capacitance of the combination shown in the figure is :
Equal potentials are applied on an iron and copper wire of same length. In order to have the same current flow in the two wires, the ratio r (iron)/r (copper) of their radii must be (Given that specific resistance of iron = $1.0 \times 10^{-7}$ ohm–m and specific resistance of copper = $1.7 \times 10^{-8}$ ohm-m)
→The ratio activity of an element becomes $1/64^{th}$ of its original value in $60 \sec.$ Then the half life period is
→Two ions have equal masses but one is singly$-$ionised and the other is doubly$-$ionised. They are projected from the same place in a uniform magnetic field with the same velocity perpendicular to the field.
→A $100\, ohm$ galvanometer gives full scale deflection at $10\, mA$. How much shunt is required to read $100\, mA$ .............. $ohm$
→In a current carrying conductor the net charge is:
According to Kirchhoff's law, at any junction in an electric circuit:
If atmospheric electric field is approximately $150 \,volt / m$ and radius of the earth is $6400 \,km$, then the total charge on the earth's surface is .......... coulomb
→Current growth in two $L-R$ circuits $(b)$ and $(c)$ as shown in figure $(a)$. Let $L_1, L_2, R_1$ and $R_2$ be the corresponding values in two circuits. Then
→It becomes possible to define potential at a point in an electric field because electric field: