MCQ
An acidified solution of $0.05 M Zn ^{2+}$ is saturated with $0.1 M H _2 S$. What is the minimum molar concentration ($M$) of $H ^{+}$required to prevent the precipitation of $ZnS$ ?

Use $K_{ sp }( ZnS )=1.25 \times 10^{-22}$ and

Overall dissociation constant of $H _2 S , K_{ NET }=K_1 K_2=1 \times 10^{-21}$

  • A
    $0.10$
  • B
    $0.15$
  • $0.20$
  • D
    $0.25$

Answer

Correct option: C.
$0.20$
c
;For ppt , $\quad\left[ Zn ^{+2}\right]\left[ S ^{-2}\right]= K _{ sp }$

$\begin{array}{l}{\left[ S ^{-2}\right]=\frac{1.25 \times 10^{-22}}{0.05}} \\ =2.5 \times 10^{-21} M \end{array}$

$H _2 S \rightleftharpoons 2 H ^{+}+ S ^{-2}$

$K _{\text {Net }}=10^{-21}=\frac{\left[ H ^{+}\right]^2 \times 2.5 \times 10^{-21}}{0.1}$

${\left[ H ^{+}\right]^2=\frac{1}{25}}$

${\left[ H ^{+}\right]=\frac{1}{5} M =0.2 M }$

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