Question
An $\alpha $-particle is accelerated through a potential difference of $200\,V$. The increase in its kinetic energy is.......$eV$
✓
Answer
c
(c) $KE = QV\, \Rightarrow KE = (2e)\,200\,V = 400\,eV$
(c) $KE = QV\, \Rightarrow KE = (2e)\,200\,V = 400\,eV$
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