- A$AgN{O_3}$
- B$N{H_4}N{O_3}$
- ✓$\left[ {Ag{{\left( {N{H_3}} \right)}_2}} \right]Cl$
- D$\left[ {Ag{{\left( {N{H_3}} \right)}_2}} \right]Br$
$AgCl + 2N{H_3} \to \mathop {[Ag{{(N{H_3})}_2}]Cl.}\limits_{{\text{diammine silver (I) chloride}}{\text{.}}} $
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$C{{H}_{3}}OH\xrightarrow{HI}C{{H}_{3}}I\xrightarrow{KCN}$
$C{{H}_{3}}CN\xrightarrow{\text{reduction}}X\xrightarrow{HN{{O}_{3}}}Y$
Assertion $A:$ A mixture contains benzoic acid and napthalene. The pure benzoic acid can be separated out by the use of benzene.
Reason $R:$ Benzoic acid is soluble in hot water.
In the light of the above statements, choose the most appropriate answer from the options given below.
Reason : Zinc has a more negative electrode potential than iron.
$(i)\,\,(CH_3)_2CH - CH_2Br \xrightarrow{{{C_2}{H_5}OH}}$ $ (CH_3)_2CH - CH_2OC_2H_5 + HBr$
$(ii)\,\,(CH_3)_2CH - CH_2Br \xrightarrow{{{C_2}{H_5}O^-}} $ $(CH_3)_2CH - CH_2OC_2H_5 + Br^-$
The mechanisms of reactions $(i)$ and $(ii)$ are respectively