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$C{H_3} - C \equiv N\xrightarrow[{E{t_2}O}]{{C{H_3}Mgl}}\xrightarrow{{{H_3}{O^ \oplus }}}$
| List $I$ Element detected | List $II$ Reagent used/Product formed |
| $A$ Nitrogen | $I.$ $Na _2\left[ Fe ( CN )_5 NO \right]$ |
| $B$ Sulphur | $II.$ $AgNO _3$ |
| $C$ Phosphorous | $III.$ $Fe _4\left[ Fe ( CN )_6\right]_3$ |
| $D$ Halogen | $IV.$ $\left( NH _4\right)_2 MoO _4$ |
Choose the correct answer from the options given below:
${\left[ {Fe{{\left( {CN} \right)}_6}} \right]^{ - 4}}\xrightarrow{{MnO_4^ - /{H^ + }}}F{e^{ + 3}} + C{O_2} + NO_3^ - $