MCQ
An aromatic compound '$A$' on treatement with aqueous ammonia and heating forms compound '$B$' which on heating with $Br_2$ and $KOH$ form a compound $C$ of molecular formula $C_6H_7N$. The structures of compound $A, \,B$ and $C$ are respectively
  • A
    $C_6H_5CH_3$,  $C_6H_5CONH_2.C_6H_5CH_2NH_2$
  • B
    $C_6H_5CHO$,  $C_6H_5CONHCH_3$,  $C_6H_5CH_2-NH_2$
  • $C_6H_5COOH$,  $C_6H_5CONH_2$,  $C_6H_5NH_2$
  • D
    $C_6H_5COOH$,  $C_6H_5NH-C_2H_5$,  $C_6H_5NH_2$

Answer

Correct option: C.
$C_6H_5COOH$,  $C_6H_5CONH_2$,  $C_6H_5NH_2$
c
${{C}_{6}}{{H}_{5}}COOH\,\xrightarrow{N{{H}_{3}}}{{C}_{6}}{{H}_{5}}COON{{H}_{4}}$ $\xrightarrow{\Delta }$ 

$\begin{matrix}
   {{C}_{6}}{{H}_{5}}-C-N{{H}_{2}}  \\
   ||  \\
   O  \\
\end{matrix}$ $\xrightarrow{B{{r}_{2}}/KOH}\,{{C}_{6}}{{H}_{5}}N{{H}_{2}}$

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