MCQ
An atom of an element $A$ has three electrons in its outermost shell and that of $B$ has six electrons in the outermost shell. The formula of the compound between these two will be
- A${A_3}{B_4}$
- ✓${A_2}{B_3}$
- C${A_3}{B_2}$
- D${A_2}{B_3}$
so according to Criss Cross rule the formula of the compound between these two will be ${A_2}{B_3}$.
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(Given : $h =6.626 \times 10^{-34} Js$ )
$2K\,Cl{O_3}\xrightarrow{{}}2KCl + 3{O_2}$ law of mass action
$(a)$ Heat of combustion reaction
$(b)$ Heat of formation reaction
$(c)$ An exothermic reaction
$(d)$ Not neutralization reaction