MCQ
An atom with atomic number $20$ is most likely to combine chemically with the atom whose atomic number is
- A$11$
- B$14$
- ✓$16$
- D$10$
✓
Answer
Correct option: C.
$16$
c
Atomic number $20$ will be distributed in electron shell as $2,8,8,2$.
Atomic number $20$ will be distributed in electron shell as $2,8,8,2$.
Its valency is $2$. It will loose this $2$ electron to gain stability and noble gas configuration. If atomic number $11$ is distributed in electron shell it will be $2,8,1$.
Atom with valence electron $1$ will loose this atom to gain stability. Hence, both ${ }_{20} X$ and ${ }_{11} X$ will gain nothing i.e. will not gain stable electronic configuration after combining with each other.
An atom with atomic number $16$ has electronic configuration as $2,8,6$. It will gain $2$ electron from ${ }_{20} X$ and complete its octet. Thus atom having atomic number $20$ will combine most likely with atom having atomic number $16$ as both will gain stable electronic configuration.
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