MCQ
An electrolytic cell contains solution of $Ag_2SO_4$ and has Platinum electrodes. A current is passed until $1.6\,g$ of $O_2$ is liberated at anode. The amount of silver deposited at cathode would be ............ $\mathrm{g}$
  • A
    $107.88$
  • B
    $1.6$
  • C
    $0.8$
  • $21.6$

Answer

Correct option: D.
$21.6$
d
At cathode $\mathrm{Ag}^{+}+\mathrm{e}^{-} \rightarrow \mathrm{Ag}$

At anode $2 \mathrm{OH}^{-} \rightarrow \mathrm{H}_{2} \mathrm{O}+\frac{1}{2} \mathrm{O}_{2}+2 \mathrm{e}^{-}$

$E_{A g}=\frac{108}{1}$  ;  $E_{O_{2}}=\frac{\frac{1}{2} \times 32}{2}=8$

$\frac{{{\text{W}}_{\text{Ag}}}}{{{\text{E}}_{\text{Ag}}}}=\frac{{{\text{W}}_{{{\text{O}}_{2}}}}}{{{\text{E}}_{{{\text{O}}_{2}}}}}\Rightarrow $ ${{\text{W}}_{\text{Ag}}}=\frac{1.6\times 108}{8}=21.6\,\text{gm}$

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