MCQ
An electromagnetic wave going through vacuum is described by $\text{E}=\text{E}_0\sin(\text{kx}-\omega\text{t}),\text{ B}=\text{B}_0\sin(\text{kx}-\omega\text{t})$ Then:
- ✓$\text{E}_0\text{k}=\text{B}_0\omega$
- B$\text{E}_0\text{B}_0=\omega\text{k}$
- C$\text{E}_0\omega=\text{B}_0\text{k}$
- DNone of these.

