MCQ
An electromagnetic wave, going through vacuum is described by $\text{E}=\text{E}_0\sin(\text{kx}-\omega\text{t}.)$ Which of the following is independent of wavelength?
- A$\text{k}$
- B$\omega$
- ✓$\frac{\text{k}}{\omega}$
- D$\text{k}\omega$
✓
Answer
Correct option: C.
$\frac{\text{k}}{\omega}$
$\text{k}=\frac{2\pi}{\lambda}$
$\omega=\frac{2\pi\text{c}}{\lambda},$ where c is the velocity of light
Hence, $=\frac{\text{k}}{2\pi}=\frac{\omega}{2\pi\text{c}}$
$\Rightarrow\frac{\text{k}}{\omega}$ is independent of the wavelength.
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