- A$1$
- B$2$
- C$3$
- ✓$4$
When $m =-3,l=3 \quad \therefore n =4$
Note: For a given value of $n, 1$ can have values $0,1,2, \ldots . .(n-1)$ and $m$ can have values $-l, \ldots .-2,-1,0,+1,+2 \ldots+l$.
For $n=4,l$ can have values $0,1,2,3$.
For a given value of $l, m$ can have values $-3,-2,-1,0,+1,+2,+3$.
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$Ag\left( s \right)/A{g^ \oplus }||C{u^{2 + }}/Cu\left( s \right)$
$A{g^ \oplus } + {e^ - } \to Ag\,;\,{E^o} = x$
$C{u^{2 + }} + 2{e^ - } \to Cu\,;\,{E^o} = y$
$E^o_{cell}$ is

$A$. The successive half lives of zero order reactions decreases with time.
$B$. A substance appearing as reactant in the chemical equation may not affect the rate of reaction
$C$. Order and molecularity of a chemical reaction can be a fractional number
$D$. The rate constant units of zero and second order reaction are $mol\, L ^{-1} s ^{-1}$ and $mol ^{-1} Ls ^{-1}$ respectively