MCQ
An electron is accelerated from rest through a potential difference such that its kinetic energy is $1.5\,eV$, then de-Broglie wavelength associated with this electron is
  • A
    $\lambda  = {10^{ - 10}}\,m$
  • B
    $\lambda  = {10^{ - 8}}\,m$
  • $\lambda  = {10^{ - 9}}\,m$
  • D
    $\lambda  = {10^{ - 7}}\,m$

Answer

Correct option: C.
$\lambda  = {10^{ - 9}}\,m$
c
$\lambda (\mathop {\rm{A}}\limits^o ) = \sqrt {\frac{{150}}{V}}  = \sqrt {\frac{{150}}{{1.5}}}  = \sqrt {100} \mathop {\rm{A}}\limits^o $

$ = 10\mathop {\rm{A}}\limits^o  = 10 \times {10^{ - 10}} = {10^{ - 9}}{\rm{m}}$

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