An electron is travelling horizontally towards east. A magnetic field in vertically downward direction exerts a force on the electron along
Easy
Download our app for free and get started
Fleming's left hand rule is used to determine the direction of force.
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1A semicircular ring of radius $R$ carrying current $i$ is placed in a magnetic field of intensity $B$ so that plane of wire is perpendicular to magnetic field as shown. Net force acting on the ring isView Solution
- 2A galvanometer of $50\, ohm$ resistance has $25$ divisions. A current of $4 \times 10^{-4}$ ampere gives a deflection of one division. To convert this galvanometer into a voltmeter having a range of $25\, volts$, it should be connected with a resistance ofView Solution
- 3A $50\, ohm$ galvanometer gets full scale deflection when a current of $0.01\, A$ passes through the coil. When it is converted to a $10\, A$ ammeter, the shunt resistance is ........... $\Omega $View Solution
- 4A charge of $2.0\,\mu C$ moves with a speed of $3.0 \times {10^6}\,m{s^{ - 1}}$ along $+ ve$ $X$ - axis $A$ magnetic field of strength $\vec B = - 0.2\,\,\hat k$ $Tesla$ exists in space. What is the magnetic force $({\overrightarrow F _m})$ on the chargeView Solution
- 5Two long parallel wires are at a distance $2d$ apart. They carry steady equal currents flowing out of the plane of the paper, as shown. The variation of the magnetic field $B$ along the line $XX’$ is given byView Solution
- 6In a hydrogen atom, an electron moves in a circular orbit of radius $5.2 \times {10^{ - 11}}\,m$ and produces a magnetic induction of $12.56\, T$ at its nucleus. The current produced by the motion of the electron will be (Given ${\mu _0} = 4\pi \times {10^{ - 7}}\,Wb/A - m)$View Solution
- 7An insulating thin rod of length $l$ has a linear charge density $\rho \left( x \right) = {\rho _0}\,\frac{x}{l}$ on it. The rod is rotated about an axis passing through the origin $(x = 0)$ and perpendicular to the rod. If the rod makes $n$ rotations per second, then the time averaged magnetic moment of the rod isView Solution
- 8Magnetic field due to semi infinite length wire at point $P$View Solution
- 9View SolutionElectrons moving with different speeds enter a uniform magnetic field in a direction perpendicular to the field. They will move along circular paths.
- 10Work done by magnetic field of $1\,tesla$ on a particle of chargs $1\,C$ moving with speed $5\,m/s$ in one second........$J$View Solution