MCQ
An electron of mass $m$ when accelerated through a potential difference $V$ has de$-$Broglie wavelength $\lambda .$ The de$-$Broglie wavelength associated with a proton of mass $M$ accelerated through the same potential difference will be
- A$\lambda^{\frac{m}{M}}$
- ✓$\lambda^{\sqrt{\frac{m}{M}}}$
- C$\lambda^{\frac{m}{M}}$
- D$\lambda^{\sqrt{\frac{M}{m}}}$
