MCQ
An element $A$ decays into element $C$ by a two step process :
$A \to B + {\;_2}H{e^4}$
$B \to C + \;2{e^ - }$
Then
- ✓$A$ and $C$ are isotopes
- B$A$ and $C$ are isobars
- C$A$ and $B$ are isotopes
- D$A$ and $B$ are isobars
$A \to B + {\;_2}H{e^4}$
$B \to C + \;2{e^ - }$
Then
$\beta $ decay increases the atomic number by $1$.
Here atomic number of $C$ is same as that of $A.$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

