MCQ
An element $A$ decays into element $C$ by a two step process :

$A \to B + {\;_2}H{e^4}$

$B \to C + \;2{e^ - }$

Then

  • $A$ and $C$ are isotopes
  • B
    $A$ and $C$ are isobars
  • C
    $A$ and $B$ are isotopes
  • D
    $A$ and $B$ are isobars

Answer

Correct option: A.
$A$ and $C$ are isotopes
a
$\alpha$ decay decreases the mass number by $4$ and atomic number by $2$,

$\beta $ decay increases the atomic number by $1$.

Here atomic number of $C$ is same as that of $A.$

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