MCQ
An element has electronic configuration $1{s^2}2{s^2}2{p^6}3{s^2}3{p^4}$. Predict their period, group and block
  • Period = $3^{rd}$, block = $p$, group = $16$
  • B
    Period =$ 5^{th}$, block = $s$, group = $1$
  • C
    Period = $3^{rd}$, block =$ p$, group = $10$
  • D
    Period = $4^{th}$, block = $d$, group = $12$

Answer

Correct option: A.
Period = $3^{rd}$, block = $p$, group = $16$
a
$(a)$ By obserbing principal quantum number $(n)$, Orbital $(s,p,d,f)$ and equating no. of ${e^ - }$’s we are able to find the period, block and group of element in periodic table.

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