Question
An element has electronic configuration $[A r] 3 d^4$ in its +3 oxidation state. What will be electronic configuration of its atom?

Answer

The electronic configuration of its atom is:
$1 s^2\ 2 s^2\ 2 p^6\ 3 s^2\ 4 s^2\ 3 d^5 \text { or }[\operatorname{Ar}] 4 s^2\ 3 d^5$.

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