Question
An element has electronic configuration [Ar] 3d4 in its +3 oxidation state. What will be electronic configuration of its atom?
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CH3CH2I + KOH(aq) → CH3CH2OH + KI
$(\text{CH}_3\text{COO})_2\text{Pb}+\text{Na}_2\text{S}\xrightarrow{\ \ \ \ \ \ }$