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STD 12 -1. Solution and colligative properties — NEET STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceNEETSTD 12 -1. Solution and colligative properties4 Marks
MCQ
An ideal solution has two components $A$ and $B$. If $A$ is more volatile than $B$ and also ${P_A}^o > {P_T}$, then the correct relation between mole fraction of $A$ in liquid $(x)$ and vapour $(y)$ phase is
  • A
    $X_A = Y_A$
  • ✓
    $X_A > Y_A$
  • C
    $X_A < Y_A$
  • D
    Nothing can be said
✓

Answer

Correct option: B.
$X_A > Y_A$
b
Total $V.P.$ of solution $=\,P^o_Ax_A\,+\,P^o_Bx_B$

Given, $P^o_A\,=\,74.7\,torr$, $P^o_B\,=\,22.3\,torr$

$n_{benzene}\,=\,1.5\,mol$, $n_{toluene}\,=\,3.5\,mol$

$n_{solution}\,=\,1.5+3.5=5\,mol$

$X_A\,=\,\frac {n_{benzene}}{n_{solution}}\,=\,\frac {1.5}{5}$

Total $V.P.$ of solution

$ = \left( {\frac{{1.5}}{5}\, \times \,74.7\, + \,\frac{{3.5}}{5}\, \times \,22.3} \right)\,torr$

$=\,(15.6+22.4)\,torr\,\,=\,38\,torr$

Mole fraction of benzene in vapour form

$=\,\frac {22.4}{38}\,=\,0.589$

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