Given, $P^o_A\,=\,74.7\,torr$, $P^o_B\,=\,22.3\,torr$
$n_{benzene}\,=\,1.5\,mol$, $n_{toluene}\,=\,3.5\,mol$
$n_{solution}\,=\,1.5+3.5=5\,mol$
$X_A\,=\,\frac {n_{benzene}}{n_{solution}}\,=\,\frac {1.5}{5}$
Total $V.P.$ of solution
$ = \left( {\frac{{1.5}}{5}\, \times \,74.7\, + \,\frac{{3.5}}{5}\, \times \,22.3} \right)\,torr$
$=\,(15.6+22.4)\,torr\,\,=\,38\,torr$
Mole fraction of benzene in vapour form
$=\,\frac {22.4}{38}\,=\,0.589$
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Statement $I:$ For $KI$, molar conductivity increases steeply with dilution.
Statement $II:$ For carbonic acid, molar conductivity increases slowly with dilution. In the light of the above statements, choose the correct answer from the options given below: