An invert sugar is
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{\begin{array}{*{20}{c}}
{CH = O\,\,\,\,\,\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}} \\
{{{(CH - OH)}_4}} \\
{\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_2} - OH}
\end{array}$ $\xrightarrow{{B{r_2}/{H_2}O}}P$ ; $P$ is - 2View SolutionHydrolysis of sucrose is called
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