MCQ
An ion has $18$ electrons in the outermost shell, it is
- ✓$C{u^ + }$
- B$T{h^{4 + }}$
- C$C{s^ + }$
- D${K^ + }$
Electronic configuration of copper $=2,8,18,1$
When copper loses one electron then it becomes a positive ion that is $Cu^+$.
No of electrons in ionic $Cu^+\,=$ atomic no. of copper $-$ no. of electrons lost
$=29-1=28$
Therefore electronic configuration of copper ion $Cu^+\, 2,8,18.$
This means that $Cu^+$ has $18$ electrons in its outermost shell.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$ \mathrm{N}_2=3.0 \times 10^{-3} \mathrm{M}, \mathrm{O}_2=4.2 \times 10^{-3} \mathrm{M} \text { and } \mathrm{NO}=2.8 \times 10^{-3} \mathrm{M} . $
$ 2 \mathrm{NO}_{(\mathrm{g})} \rightleftharpoons \mathrm{N}_{2(\mathrm{~g})}+\mathrm{O}_{2(\mathrm{~g})}$
If $0.1 \mathrm{~mol} \mathrm{~L} \mathrm{~L}^{-1}$ of $\mathrm{NO}_{(\mathrm{g})}$ is taken in a closed vessel, what will be degree of dissociation ( $\alpha$ ) of $\mathrm{NO}_{(\mathrm{g})}$ at equilibrium?
(Given : atomic number $Sm =62 ; Eu =63 ; Tb =65 ; Gd =64, Pm =61 \text { ) }$
$A.$ $Sm$ $B.$ $Eu$ $C.$ $Tb$ $D.$ $Gd$ $E.$ $Pm$
Choose the correct answer from the options given below: