MCQ
An irrational number between $\sqrt{2}$ and $\sqrt{3}$ is:
  • A
    $5^{\frac{1}{4}}$
  • B
    $(\sqrt{2}+\sqrt{3})$
  • C
    $6^{\frac{1}{4}}$
  • D
    $\sqrt{2}\times\sqrt{3}$ 

Answer

  1. $6^{\frac{1}{4}}$
    Solution:
    $\sqrt{2}$ and $\sqrt{3}$
    $=2^{\frac{1}{2}}$ and $3^{\frac{1}{2}}$
    $=2^{\frac{2}{4}}$ and $3^{\frac{2}{4}}$
    $=4^{\frac{1}{4}}$ and $9^{\frac{1}{4}}$
    Irrational between $\sqrt{2}$ and $\sqrt{3}$ is $6^{\frac{1}{4}}$

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