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Laws of Motion — PHYSICS STD 9 — Question

ICSE BoardEnglish MediumSTD 9PHYSICSLaws of Motion1 Mark
MCQ
An object falling freely from rest reaches ground in $2 s .$ If acceleration due to gravity is $9.8\ m s ^{-2}$, then the velocity of object on reaching the ground will be
  • A
    $9.8\ m s ^{-1}$
  • B
    $4.9\ m s ^{-1}$
  • ✓
    $19.6\ m s ^{-1}$
  • D
    Zero
✓

Answer

Correct option: C.
$19.6\ m s ^{-1}$
An object falling freely from rest reaches ground in $2 s .$ If acceleration due to gravity is $9.8\ m s ^{-2}$, then the velocity of object on reaching the ground will be $19.6\ m s ^{-1}$ METHOD: Given, $u=0\ g=9.8 m / s ^2$ Time $t =2 s$ Let $' v '$ be the velocity of object on reaching the ground. Using the first equation of motion, $v=u+g t$ We get, $v=0+(9.8)(2)$ Or, $v=19.6\ m / s$.

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