Question
An object is moving along a straight line with uniform acceleration. The following table gives the velocity of the object at various instants of time:
Time (in sec.):
$0$
$1$
$2$
$3$
$4$
$5$
$6$
Velocity (in m/s):
$2$
$4$
$6$
$8$
$10$
$12$
$14$
Plot the graph. From the graph,
  1. Find the velocity of the object at the end of $2.5$ seconds.
  2. Calculate the acceleration.
  3. Calculate the distance covered in the last $4$ seconds.

Answer

$\text{a}=\frac{\text{v}-\text{u}}{\text{t}}$$\text{a}=\frac{4-2}{1}=2\text{m/s}^2$
Now for,
$\text{t}=2.5$
$\text{a}=\frac{\text{v}-\text{u}}{\text{t}}$
$2=\frac{\text{v}-2}{2.5}$
$5=\text{v}-2$
$\text{v}=7$

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