MCQ
An object is thrown along a direction inclined at an angle of ${45^o}$ with the horizontal direction. The horizontal range of the particle is equal to
  • A
    Vertical height
  • B
    Twice the vertical height
  • C
    Thrice the vertical height
  • Four times the vertical height

Answer

Correct option: D.
Four times the vertical height
d
(d) $R = 4H\cot \theta $

if $\theta = 45^\circ $ then $R = 4H\cot (45^\circ ) = 4H$

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