An observer is moving towards the stationary source of sound, then
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(b) Apparent frequency in this case  $n' = \frac{{n(v + {v_O})}}{v}$

$\because$ $\frac{{v + {v_0}}}{v} > 1$ ==> $\frac{{n'}}{n} > 1$ i.e. $n' > n$.

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