MCQ
An optically active compound $'X'$ has molecular formula $C_4H_8O_3$. It  evolves $CO_2$ with $NaHCO_3. 'X'$ reacts with $LiAlH_4$ to give an achiral  compound. $'X'$ is 
  • A
    $\begin{matrix}
       C{{H}_{3}}C{{H}_{2}}CHCOOH  \\
       |  \\
       \,\,\,OH  \\
    \end{matrix}$
  • B
    $\begin{matrix}
       C{{H}_{3}}CHCOOH  \\
       |\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,  \\
       Me\,\,\,\,\,\,\,\,\,\,  \\
    \end{matrix}$
  • $\begin{matrix}
       C{{H}_{3}}CHCOOH  \\
       |\,\,\,\,\,\,\,\,\,\,\,\,\,\,  \\
       \,\,C{{H}_{2}}OH  \\
    \end{matrix}$
  • D
    $\begin{matrix}
       C{{H}_{3}}CHC{{H}_{2}}COOH  \\
       |\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,  \\
       OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,  \\
    \end{matrix}$

Answer

Correct option: C.
$\begin{matrix}
   C{{H}_{3}}CHCOOH  \\
   |\,\,\,\,\,\,\,\,\,\,\,\,\,\,  \\
   \,\,C{{H}_{2}}OH  \\
\end{matrix}$
c
$\underset{(X)}{\mathop{\begin{matrix}
   C{{H}_{3}}-CH-C{{O}_{2}}H  \\
   |\,\,\,\,\,\,\,\,\,  \\
   \,\,\,\,\,\,\,\,\,\,\,\,\,\,C{{H}_{2}}-OH  \\
\end{matrix}}}\,$  $\xrightarrow{LAH}$  $\begin{matrix}
   C{{H}_{3}}-CH-C{{H}_{2}}-OH  \\
   |\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,  \\
   \,C{{H}_{2}}-OH  \\
\end{matrix}$

$\underset{(X)}{\mathop{\begin{matrix}
   C{{H}_{3}}-CH-C{{O}_{2}}H  \\
   |\,\,\,\,\,\,\,\,\,  \\
   \,\,\,\,\,\,\,\,\,\,\,\,\,\,C{{H}_{2}}-OH  \\
\end{matrix}}}\,$ $\xrightarrow{NaHC{{O}_{3}}}$ $\begin{matrix}
   C{{H}_{3}}-CH-CO_{2}^{\Theta }+C{{O}_{2}}  \\
   |\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,  \\
   \,\,C{{H}_{2}}-OH  \\
\end{matrix}$

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