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An optically active compound $X$ has molecular formula $C_4H_8O_3.$ It evolves $CO_2$ with $NaHCO_3.$  $'X' $ Reacts with $LiAlH_4$ to give an achiral compound. $'X'$ is

• A
  $\begin{array}{*{20}{c}}
  {C{H_3} - C{H_2} - CH - COOH}\\
  {\,\,\,\,|}\\
  {\,\,\,\,\,\,\,OH}
  \end{array}$
• B
  $\begin{array}{*{20}{c}}
  {C{H_3} - CH - COOH}\\
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,}\\
  {\,\,\,\,\,\,\,\,\,C{H_2} - OH}
  \end{array}$
• ✓
  $\begin{array}{*{20}{c}}
  {C{H_3} - CH - COOH}\\
  \,\,\,\,{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}\\
  \,\,\,\,{OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
  \end{array}$
• D
  $\begin{array}{*{20}{c}}
  {C{H_3} - CH - C{H_2} - COOH}\\
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}\\
  {OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
  \end{array}$