MCQ
An optically active compound $'X'$ having molecular formula $C_4H_8O_3$ it evolves $CO_2$ with $NaHCO_3.\,'x'$ on treatment with $LiAlH_4$ gives achiral compound then $'x'$ is
- A

- B

- ✓

- D






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$\mathrm{HF}, \mathrm{H}_2 \mathrm{O}, \mathrm{SO}_2, \mathrm{H}_2, \mathrm{CO}_2, \mathrm{CH}_4, \mathrm{NH}_3, \mathrm{HCl}, \mathrm{CHCl}_3, \mathrm{BF}_3$

$(i)$ Pure solvent $\to$ separated solvent molecules $\Delta$ $H_1$
$(ii)$ Pure solute $\to$ separated solute molecules$\Delta$ $H_2$
$(iii)$ Separated solvent and solute molecules $\to$ solution $\Delta H_3$ Solution so formed will be ideal if