Question
An organic compound (A) molecular formula $C _3 H _6 O$ is resistant to oxidation but form a compound $(B)\left( C _3 H _8 O \right)$ on reduction ( B $)$ reacts with HBr to form a bromide $(C)$ which on treatment with alcoholic KOH forms an alkene $(D)\left(C_3 H _6\right)$. Deduce the structures of $A, B, C$ and $D$.