Question
An organic compound 'A' (molecular formula C3H6O) is resistant to oxidation but forms a compound 'B' (
C3H8O) on reduction. 'B' reacts with HBr to form a bromide'C' which on treatment with alcoholic KOH forms an alkene 'D' (C3H6). Deduce the structures of A, B, C and D.

Answer

Structure of A, B, C and D are deduced in the following manner.
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