MCQ
An organic compound contains carbon, hydrogen and oxygen. Its elemental analysis gave $C, 38.71\%$ and $H, 9.67\%.$ The empirical formula of the compound would be
- A$CHO$
- B$CH_4O$
- ✓$CH_3O$
- D$CH_2O$
✓
Answer
Correct option: C.
$CH_3O$
c
$C \quad 38.71 \quad 12 \quad 38.71 / 12 \quad 3.22 / 3.22=1$
$C \quad 38.71 \quad 12 \quad 38.71 / 12 \quad 3.22 / 3.22=1$
$H \quad 9.67 \quad \;\;1 \;\;\quad 9.67 / 1 \;\;\quad 9.67 / 3.22=3$
$O\quad 51 .62\quad 16\quad 51.62 / 16\quad 3.22 / 3.22=1$
Hence the empirical formula of the compound would be $C H_{3} O$
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