An X- ray machine has an accelerating potential difference of 25,… - Vidyadip

MCQ

An $X-$ ray machine has an accelerating potential difference of $25,000$ volts. By calculation the shortest wavelength will be obtained as.......$\mathop A\limits^o $ ($h = 6.62 \times {10^{ - 34}}$ J-sec; e = $1.6 \times {10^{ - 19}}$coulomb)

A
$0.25$
✓
$0.50 $
C
$1$
D
$2.50$

✓

Answer

Correct option: B.

$0.50 $

b
(b) ${\lambda _{\min }} = \frac{{hc}}{{eV}} = \frac{{12375}}{V}\,{Å}$ $ = 0.495\,\,{Å} \approx 0.5\,{Å}$

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