MCQ
$\angle \,FAsF$ bond angle in $AsF_3Cl_2$ molecule is
- ✓$90^o$ and $180^o$
- B$120^o$
- C$90^o$
- D$180^o$
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$H_2C = CH - CH_2 - I \xrightarrow[CC{{l}_{4}}]{HI(excess)}$

