- A$6.62\times10^{-34}\, J\, sec$
- B$3.31\times10^{-27}\, erg.\, sec.$
- C$1.054\times10^{-27}\, erg.\, sec.$
- ✓$2.108\times10^{-27}\, erg.\, sec.$
$\therefore \quad \mathrm{mvr}=\frac{2 \times 6.62 \times 10^{-27}}{2 \times 3.14}$
$=2.108 \times 10^{-27} \text { erg. sec }$
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$2 \mathrm{Fe}_{(\mathrm{s})}+\frac{3}{2} \mathrm{O}_{2(\mathrm{~g})} \rightarrow \mathrm{Fe}_2 \mathrm{O}_{3(\mathrm{~s})}, \Delta \mathrm{H}^{\mathrm{o}}=-822 \mathrm{~kJ} / \mathrm{mol}$
$\mathrm{C}_{(\mathrm{s})}+\frac{1}{2} \mathrm{O}_{2(\mathrm{~g})} \rightarrow \mathrm{CO}_{(\mathrm{g})}, \Delta \mathrm{H}^{\mathrm{o}}=-110 \mathrm{~kJ} / \mathrm{mol}$
Then enthalpy change for following reaction
$3\mathrm{C}_{(\mathrm{s})}+\mathrm{Fe}_2 \mathrm{O}_{3(\mathrm{~s})} \rightarrow 2 \mathrm{Fe}_{(\mathrm{s})}+3 \mathrm{CO}_{(\mathrm{g})}$