Question
Angular speed of second hand of a clock is radian per second.
Explanation:
The angular velocity is independent of the clock size, however for larger clocks the linear velocity of the pointers at the end of the hands will be greater. The second hand goes through $2\pi$ radians in 1min, or $2\pi$ radian/ 60 seconds, So, $\omega=\frac{\pi}{30}\text{ rad}.\text{s}^{-1}=0.03\text{ rad.s}^{-1}.$Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.