
Figure $\xrightarrow[{pyridine}]{{C{H_3}COCl}}$ $P$ $\xrightarrow[{C{H_3}COOH}]{{B{r_2}}}Q\,\xrightarrow{{{H_3}{O^ + }}}R$


$\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad$(Yellow coloured compound)
Consider the above reaction, the Product $"P"$ is: