Question
$a^p× b^q= (ab)^{pq}$
✓
Answer
$RHS = (ab)^{pq}$
Using law of exponents, $(ab)^m= a^m× b^m$ [$\because$ a is non-zero integer]
$\therefore$ $(ab)^{pq}= (a)^{pq}× (b)^{pq}$
$LHS ≠ RHS$
Using law of exponents, $(ab)^m= a^m× b^m$ [$\because$ a is non-zero integer]
$\therefore$ $(ab)^{pq}= (a)^{pq}× (b)^{pq}$
$LHS ≠ RHS$
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