Download App

3. Classification of elements and periodicity in properties — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistry3. Classification of elements and periodicity in properties1 Mark
MCQ
Aqueous solutions of two compounds $M_1 - O - H$ and $M_2 - O - H $ are  prepared in two different beakers. If, the electronegativity of $M_1 = 3.4, M_2 =  1.2, O = 3.5$ and $H = 2.1,$ then the nature of two solutions will be respectively
  • ✓
    acidic, basic
  • B
    acidic, acidic
  • C
    basic, acidic
  • D
    basic, basic
✓

Answer

Correct option: A.
acidic, basic
a
$(a)$ The electronegativity difference between $M_1$ and $O$ is $0.1,$ which  indicates $M_1 - O$ bond will be covalent, since $O-H$ bond having more ionic  character thus bond will break and $H^+$ ions will release and acidic solution is  formed. Whereas difference between electronegativity of $M_2 - O$ bond is $2.3,$ thus, $M_2-OH$ bond will break. Hence, solution will be basic in nature.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from 3. Classification of elements and periodicity in properties→3. Classification of elements and periodicity in properties — all question types→Chemistry STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

Which of the following compounds will exhibit cis-trans isomerism
→
In the commercial electrochemical process for aluminium extraction, the electrolyte used is
→
Ionization energy is highest for
→
The ratio of the radius of the first three Bohr orbits is
→
In which of the following molecule electron density on oxygen atom is not correctly mentioned ?
→
Which of the following has the same mass as that of an electron
→
The number of moles of oxygen in $1\;L$ of air containing $21\%$ oxygen by volume, in standard conditions, is
→
Which of the following is not possible
→
In which one of the following equilibria, $K_p \ne K_c$ ?
→
$K$ for the synthesis of $HI$ is $50$ $K$ for dissociation of $HI$ is
→