MCQ
Area bounded between the curve $x^2=y$ and the line $y=4 x$ is:
  • $\frac{32}{3}\text{sq}$ unit
  • B
    $\frac{1}{3}\text{sq}$ unit
  • C
    $\frac{8}{3}\text{sq}$ unit
  • D
    $\frac{16}{3}\text{sq}$ unit

Answer

Correct option: A.
$\frac{32}{3}\text{sq}$ unit
Given curves are $x^2=y$ and $y=4 x$
Intersection points are $(0, 0)$ and $(4, 16)$
$\therefore$ Required area
$=\int\limits^4_0(4\text{x}-\text{x}^2)\text{dx}$
$=\Big[\frac{4\text{x}^2}{2}-\frac{\text{x}^3}{3}\Big]^4_0$
$=\Big[32-\frac{64}{3}\Big]$
$=\frac{32}{3}\text{sq}$ unit

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