MCQ
Area of circle $x^2+y^2=4$ :
  • A
    $2 \pi$
  • B
    $16 \pi$
  • $4 \pi$
  • D
    $\frac{\pi}{4}$

Answer

Correct option: C.
$4 \pi$
(C) $4 \pi$
Circle $x^2+y^2=4$
$
\begin{aligned}
\therefore \quad(x)^2+(y)^2 & =(2)^2 \\
\text { Area of circle } & =\pi(\text { radius })^2=\pi(2)^2 \\
& =4 \pi
\end{aligned}
$

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